13x^2=148

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Solution for 13x^2=148 equation:



13x^2=148
We move all terms to the left:
13x^2-(148)=0
a = 13; b = 0; c = -148;
Δ = b2-4ac
Δ = 02-4·13·(-148)
Δ = 7696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{7696}=\sqrt{16*481}=\sqrt{16}*\sqrt{481}=4\sqrt{481}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{481}}{2*13}=\frac{0-4\sqrt{481}}{26} =-\frac{4\sqrt{481}}{26} =-\frac{2\sqrt{481}}{13} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{481}}{2*13}=\frac{0+4\sqrt{481}}{26} =\frac{4\sqrt{481}}{26} =\frac{2\sqrt{481}}{13} $

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